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Write two maths.
If the speed of a car is x, the speed of b car is x+ 10.

Equation: (2+4)x+4(x+ 10)=460, and the solution is x=42, that is, the speed of vehicle A is 42 kilometers per hour.

2.80000÷50= 1600 (m/min)? The approaching speed of two cars.

(80000÷2)÷(50+ 16 2/3)=600 (m/min)? crawl speed

1600-600 = 1000 (m/min) = 1 (km/min) the speed of the express train.

80- 1× (50+ 16 and 2/3)=40/3= 13 and 1/3 (km) The distance between the express train and the second place.