1) 1/2absinC= root number three; A 2+B 2-2 ABC OSC = C 2, and the two formulas are solved simultaneously to get a=b=2.

2) because sinB=2sinA, b=2a, a 2+b 2-2abcosc = c 2, and then the simultaneous solution gives a=2 times two thirds, and b = 4 times two thirds, so the area S= 1/2absinC=2 times two thirds.