Solution: From 2x-3y+4 = 0:

Y=﹙2X+4﹚/3=﹙2/3﹚X+4/3，

Two straight lines are perpendicular,

∴ 2/3 * k =- 1, and the solution is k =-3/2.

∴L linear equation can be set as: y =-3/2 x+b,

Then substitute the point (-1, 2) into the L equation to get:

b= 1/2，

∴L equation: y =-3/2 ~ x+ 1/2.

Multiply both sides of y =-3/2x+ 1/2 by 2 to get:

2y=-3x+ 1

Move to the same side, that is:

3X+2Y- 1=0