There is a remainder in the math problem of the third grade of primary school students. The even division is 480 ÷ 9 = 53 ÷ 3 480 ÷ 3 =160 ÷ 3 = 53 ÷1.Which is correct? Please give us some advice.

Careful analysis:

480 ÷ 9 = 53 3 and 480÷3÷3= 160÷3=53 remainder 1 will do.

1, correct analysis: using the last quotient (quotient) 53x (divisor) 9=477, the dividend is 480, so adding the remainder 3 equals the dividend 480. Checking calculation: (53×9)+3=480

2,480 ÷ 3 ÷ 3 = 53 remainder 1

160÷3=53 1

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