The first question is that there is no proposition: if AC

Proof of true proposition: △ = b 2-4ac because ac

the second question

The sufficient condition that P is Q shows that P can deduce the value range of X of Q, and P is-2 ≤ X ≤ 6 = > 2-m≥-2 and 2+m ≤ 6 = > M< four

And because m > m ≥ 2-m of 2+m; 0 so 0

M=5 q must be true, so P is false =>x>6 or X.