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Funnel math problem
1. Analysis: As long as the vertex angles of the cone surrounded by filter paper and the funnel are equal, they can overlap.

Vertex of cone surrounded by filter paper:

Fold the filter paper twice and divide it into four parts. Now there are three overlapping parts, so the perimeter of these three layers only accounts for 1 point of the four parts, plus the other half 1 layer, so the perimeter of the cone bottom circle is half of that before folding:1/2 * 2π r =1/2 * π.

Radius of base circle =5π/2π=5/2 bus = radius of great circle =5.

On the cross section, within the right triangle surrounded by the height, radius and generatrix of the cone: radius/generatrix = 1/2.

So: the vertex angle of the triangle =30 degrees.

The vertex angle of the triangle on the cross section of the cone =2*30=60 degrees.

Similarly, the funnel radius/generatrix =3/6= 1/2, then the funnel vertex angle is 60 degrees.

So they can overlap!

2, S fan = (LR)/2 (L is the arc length of the sector)

Funnel center angle =L/ circumference *360 degrees

L=2πR=2π* 1/2*7.2=7.2π

Perimeter =2πR=2π*6= 12π

Funnel central angle =7.2π/ 12π*360 degrees =2 16 degrees.

S fan = (n/360) π * r * r (n is the degree of central angle)

s fan =(2 16/360)π* 5 * 5 = 15π。

S circle =πR*R=π*5*5=25π.

S circle -S fan =25π- 15π= 10π.

The extra area is folded in half and overlapped on the cone, so that together with the original layer, * * * is three layers.

So the area of each layer in the overlapping part = 1/2* 10π=5π.

5π is approximately equal to 5*3. 14= 15.7.