The absolute value of 1.(20 12 Jinan senior high school entrance examination)-12 is ()
A. 12B。 -12 degrees Celsius
(20 12 Sanming Senior High School Entrance Examination) Among the four numbers -2, -0 and 2, the largest number is ().
A.2B。 -C.0D.2
3. The result of calculating-1×(-+ 1-) is ().
A.-B.0C. 1D。
4.(20 12 Laiwu Senior High School Entrance Examination) A large number of facts have proved that environmental pollution control is urgent. About 142000 tons of sewage is discharged into rivers, lakes and seas every second in the world, and the general scientific notation of 142000 is expressed as ().
A. 1.42× 105B
C. 142× 103D
5. In -(-5), -(-5)2, -|-5|, (-5)3, the negative number is ().
A.0 B. 1 C.2 D.3
6. If A =-2× 32, B = (-2× 3) 2 and C =-(2× 3) 2, then the correct size relationship is ().
A.a & gtb & gtcB.b>。 c & gta
C.b & gta & gtcD.c & gta & gtb
7.(20 12 Erdos senior high school entrance examination) There is a string of colored beads, which are repeatedly arranged in the order of white, yellow and blue, and some are placed in a box, as shown in the figure, so the number of beads placed in the box may be ().
a . 20 10b . 20 1 1c . 20 12d . 20 13
Fill in the blanks (5 points for each small question, 25 points for * * *)
8.(20 12 Shanghai senior high school entrance examination) Calculation |- 1|=.
9. A person's passbook originally had 5000 yuan. If the deposit record is positive and the withdrawal record is negative, the deposit and withdrawal situation of this person in the first half of the year is +500 yuan, -300 yuan,+1, 200 yuan and -600 yuan, so this person has deposits.
10. If a*b=a-b2, then (1*2)*(-3)=.
1 1. If |x-|+(2y+ 1)2=0, the value of x2+y3 is.
12. A TV station launched the program "Happy Family Weekend". The program stipulates that families participating in the program must perform a program, and the audience is the judge. The sign of+10 that supports families to continue to participate in the next program, and the sign of-10 that does not support families to participate in the next program. Then, according to the score, determine the families who will participate in the next program. The total score of the families who finally participated in the next program is 1260. It is known that the number of people who display the-10 sign is 26, so the audience who support this family to participate in the next program is more than those who don't.
Iii. Answering questions (***47 points)
13.( 12 points) Calculate the following questions:
( 1)- 10+8÷(-2)2-(-4)×(-3).
(2)(2-4- 1)÷(- 1).
(3)÷(-2)-×(- 1)-0.5÷2×.
14.( 10) During the "Eleventh" Golden Week, a merchant shop vigorously promoted sales. The following table shows the fluctuation of turnover on the current day and the previous day (unit: 10,000 yuan). It is known that the turnover on September 30th was 260,000 yuan:
10/0/month 1 2 3 4 5 6 7
4320- 1-3-5
(1) When is the lowest turnover during the Golden Week? What's the turnover that day? (Answer directly, don't write the process)
(2) What is the average daily turnover during the Golden Week?
15.( 12 points) 8 boxes of oranges, based on each box 15kg. The excess kilograms are recorded as positive numbers, and the insufficient kilograms are recorded as negative numbers. Now it is recorded as follows (unit: kg): 1.2, -0.8, 2.3, 65438+.
16.( 13 points) Students, we have studied the square grid of n×n, and obtained the expression of the total number of squares in the grid as 12+22+32+…+n2, but when n is 100, how should the specific number of squares be calculated? Let's explore and solve this problem together. First of all, we already know that 0×1+/kloc-0 /× 2+2× 3+…+(n-1)× n = n (n+1) (n-1
(1) observation conjecture:
12+22=( 1+0)× 1+( 1+ 1)×2= 1+0× 1+2+ 1×2
=( 1+2)+(0× 1+ 1×2)
12+22+32=( 1+0)× 1+( 1+ 1)×2+( 1+2)×3
= 1+0× 1+2+ 1×2+3+2×3
=( 1+2+3)+(0× 1+ 1×2+2×3)
12+22+32+42=( 1+0)× 1+( 1+ 1)×2+( 1+2)×3+
= 1+0× 1+2+ 1×2+3+2×3+
=( 1+2+3+4)+( )