X satisfies the following relationship.
﹙x/4﹚? 0? 5+[﹙20-x﹚/4]? 0? 5= 12
x? 0? 5/ 16﹢﹙400-40x﹢x? 0? 5﹚/ 16= 12
x? 0? 5﹢400﹣40x﹢x? 0? 5=272
2x? 0? 5-40x﹢ 128=0
x? 0? 5-20x﹢64=0
﹙x-40﹚﹙x- 16﹚=0
X = 4 or X = 16.