Coordinates of point C: x=(0+6)/2=3, y=(0+0)/2=0. So c (3 3,0).
The coordinate of the symmetrical point C' of point C about the Y axis is (-3,0).<
Coordinates of point C: x=(0+6)/2=3, y=(0+0)/2=0. So c (3 3,0).
The coordinate of the symmetrical point C' of point C about the Y axis is (-3,0).
Connect C'D and cross the y axis at point p.
As shown in the figure, the coordinate of point P is (0,2).
In Rt△C'CD
C'C=6,CD=4
According to Pythagorean Theorem: C'D=√(6? +4? )=√52=2√ 13