Mathematical problems of linear functions</p><p>Coordinates of point C: x=(0+6)/2=3, y=(0+0)/2=0. So c (3 3,0).</p><p>The coordinate of the symmetrical point C' of point C about the Y axis is (-3,0).<

Mathematical problems of linear functions

Coordinates of point C: x=(0+6)/2=3, y=(0+0)/2=0. So c (3 3,0).

The coordinate of the symmetrical point C' of point C about the Y axis is (-3,0).<

Mathematical problems of linear functions

Coordinates of point C: x=(0+6)/2=3, y=(0+0)/2=0. So c (3 3,0).

The coordinate of the symmetrical point C' of point C about the Y axis is (-3,0).

Connect C'D and cross the y axis at point p.

As shown in the figure, the coordinate of point P is (0,2).

In Rt△C'CD

C'C=6，CD=4

According to Pythagorean Theorem: C'D=√(6? +4? )=√52=2√ 13