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Math problem in the second day of junior high school: the solution of 54 under the root number of 6×x+3 and 3 = 3×x+ is x = _ _ _ _
(Square root of 6) x+3 radical number 3= (radical number 3)x+ radical number 54

Solution: (radical number 2) (radical number 3)x+3 (radical number 3)= (radical number 3)x+3 (radical number 2) (radical number 3)

(radical number 2)x+3=x+3 (radical number 2)

(radical number 2) x-x = 3 (radical number 2)-3

[(radical number 2)- 1] x = 3 [(radical number 2)- 1]

x=3 .

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