① According to the meaning of the question, the liquid pressure at the bottom of the two cups is equal, that is, p 1=p2. If the cup is cylindrical, G=F=ps shows G 1'=G2'.

Because the cup is in the shape shown in the figure, the gravity of the liquid in A and B is g1= g1'-△ g1',G2 = G2 '-△G2 '；;

Because △g 1'=ρ 1△V, △ G2' = ρ 2 △ v; (△V is the volume of the concave part of the cup)

∫ρ 1:ρ2 = 5:4, that is ρ 1 > ρ 2,

∴△g 1′>△g2′，

∴m 1