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An application problem of binary linear equations in mathematics
Design: Rent 42 buses X and 60 buses Y..

42x+60y & gt; 385

Because 42 buses are rented separately, 385 people need 10 cars, and the cost is 3200 yuan;

Rent a 60-seat bus alone, 385 people need 7 cars, and the cost is 3220 yuan;

So: 320 x+460 y

x+y=8

Solution: 18x

14x & gt; 48

X=4, y=4 or x=5, y=3.

When renting four 42-seat buses and four 60-seat buses, the number of seats is 408, and the total cost is 3 120 yuan.

When renting five 42-seat buses and three 60-seat buses, the number of seats is 390, and the total cost is 2980 yuan.

Therefore, five 42-seat buses and three 60-seat buses were rented.