If xy is not equal to 0, x+y is not equal to 0, and 1/x+ 1/y is inversely proportional to x+y, what is the relationship between the square of (x+y) and the square of X +y?

Solution: If xy is not equal to 0, then neither X nor Y is equal to 0.

If x+y is not equal to 0, then x and y are not opposites.

If 1/x+ 1/y is inversely proportional to x+y, 1/x+ 1/y = a/(x+y), and the square of (x+y) = axy (a is a positive integer).

From the square of (x+y) = axy: the square of x+the square of y = (a-2)xy.

Then, when a= 1, the square of (x +y) and the square of x+y are reciprocal.

When a=2, it is meaningless.

A & gtOr =3, [(x+y) squared ]-[x squared +y squared ]= 2xy.