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I made up with math.
The probability of hitting at least one of the three shots.

The probability of miss is:1/3x1/3x1/3 =1/27.

So the probability of at least one hit = 1- 1/27 = 26/27.

Of the four bullets, the probability of three consecutive hits.

There are two cases where there are only three consecutive hits: the first miss and the fourth miss, and the probability of these two cases is the same:

So the probability of just three consecutive hits is: 2×1/3× 2/3 * 2/3 =16/81.