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Fourth, mathematics supplementary exercise answers
(1) Scheme I 4* 150+6*60=600+360=960 (yuan)

Scheme 2:10 *100 =1000 (yuan)

It is also possible: 4 adults 1 child buy tickets according to scheme 2, and the remaining 5 children buy tickets according to scheme 1, which costs the least.

5* 100+5*60=500+300=800 (yuan) This is the best answer.

(2) Scheme 1: 6 *150+4 * 60 = 900+240 =1140 (yuan).

Scheme 2:10 *100 =1000 (yuan)

Not bad: six adults buy tickets according to scheme 2, and four children buy tickets according to scheme 1, which costs the least.

6* 100+4*60=600+240=840 (yuan) This is the best answer.