When k>0, the image is located in the first and third quadrants respectively. In the same quadrant, Y decreases with the increase of X; When k < 0, the image is located in the second and fourth quadrants respectively, and in the same quadrant, y increases with the increase of x. K>0, function in x
Extended data:
Suppose that the solution X of the equation can be written in the form of x=a-b, where A and B are undetermined parameters.
Substitute it into the equation and we have it.
a3-3a2b+3ab2-b3=p(a-b)+q
Complete sorting
a3-b3 =(a-b)(p+3ab)+q
According to the theory of quadratic equation, A and B can be properly selected, so that when x=a-b,
3ab+p=0. So the above formula becomes
a3-b3=q
Multiply both sides by 27a3, and you get
27a6-27a3b3=27qa3
P=-3ab indicates that
27a6 + p3 = 27qa3
This is a quadratic equation about a3, so A can be solved. Then b and root x can be solved.
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