The four teams played a single round robin, * * * played six games, each game was flat, and six games * * * 12 points; Every game is a winner, and the score of six games is 18, so the total score is 12-18.

The scores of four teams are continuous natural numbers, while 1+2+3+4 = 10, 2+3+4+5= 14, 3+4+5+6 = 18. Total score of four teams 14.

A got 5 points, B got 4 points, C got 3 points and D got 2 points. If you score 3 points from C, you can know that C is tied with A, B and D; If you score 2 points from d, you can know that d is equal to a, and B 1 and 1 are negative; The scores of A and B are higher than 3 points, which means that A and B each win 1 game, 5=3+ 1+ 1, 4=3+ 1+0, so A 1 wins 2 levels, and B 1.

B the total score is 4 points.

Assuming that A gets 6 points, B gets 5 points, C gets 4 points and D gets 3 points, we can know that D and ABC are tied, C is 3+ 1+0 B is 3+1+/A's 6 points can only be 3+3+0.

A can only win CB by winning two games, which is inconsistent with B's 3+ 1+ 1 and D's 1+ 1.

So there is no such thing as four teams playing 3, 4, 5 and 6.