2. Solution:? AB=AC, AD equally divided? BAC,? AD is also the high school line here in BC. BD= 1/2BC=5 cm,? ADB=90? . Again? B=45? , bad =45? ,? AD=BD=5cm。
3. proof: in Rt△ACB, because? A=30? ,? ACB=90? , so? B=60? ,BC = 1/2ab。 In Rt△BDC, because? B=60? ,? BDC=90? , so? BCD=30? So BD= 1/2 BC, so BD= 1/2? 1/2AB= 1/4AB。
Bian Xiao suggested: