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How to solve the charter problem in the second book of fourth grade mathematics
The solution to the problem of chartering is as follows.

1, first divided by the largest number (the number of large ships) mainly depends on the remainder. Suppose a * * 32 people, a boat 24 yuan and a ship 30 yuan: 32÷6 equals 5 (bars) ... two (people).

2. As mentioned above, that is five big ships and one small boat: 30×5+24 times 174 yuan. Vacant seats will save money: two people in a small boat and six people in a big boat can also save money by arranging them into two small boats: four big boats: 30×4 equals 120 yuan, and two small boats: 24×2 equals 120+48 equals 160 yuan in 48 yuan.