Count five boys first, and there are five in the row! = 120 species, counting girls and boys who cut in line in the middle, both ends can't stand, so there are only four vacancies for cutting in line, and girls can't be adjacent, so four are given to three girls, 4*3*2=24 species, 24* 120=2880.

First, there are four people except A, B and C, a total of four! =24 kinds, then Party A, Party B and Party C still cut in line, because they are not adjacent, so each vacancy can only stand 1 person, a total of ***5 vacancies, 5*4*3=60 kinds, 24*60= 1440.

Since each box is not empty and the balls are the same, we put one in each box first. Then the problem becomes, put five identical balls into five boxes. There is no particularly good calculation method. Let's list them. (5,0,0), (4, 1, 0), (3,2,0), (3, 1, 1), (2,2, 1), where a number is repeated.

Hope to adopt, thank you.