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Mathematical analysis of sixth grade in primary school
Analysis:

1, shadow area = large square area-circular area+small square area;

2. When the square area = 8m× 8m,

3. Circular area =0.25πd? , diameter d= square side length = 8m

4, small square area = side length x side length, side length = circle diameter /√2 = 8m/√ 2.

shaded area

= large square area-circular area+small square area

= 8m x 8m-0.25xπ x (8m)? +(8m /√2)?

=64- 16π+32 (m2)

=96- 16π (m2)

= 16(6π) m?