You can make full use of the conditions given in the question.

The volume of round steel is equal to the volume of 9 cm water in a cylindrical bucket, and the area of the bottom of the cylinder is 9 cm.

After pulling out a part, the water surface dropped by 4 cm. That is, the volume is reduced by the area at the bottom of the cylinder ×4.

The volume is reduced by four-ninth of the total volume, indicating that the height of the pull-out is also four-ninth of the total height.

Total height: 8÷4/9= 18cm.

Volume 3. 14x5? × 18= 14 13 cubic centimeter

Just find the equivalence relation. Under the condition of constant bottom area, the height is reduced and the volume is reduced.