So 2π× 12+2πh=8π, and the solution is H = 3.
Because AA 1⊥ bottom ACB, AC is the projection of A 1C on the bottom ACB.
Therefore, ≈A 1CA is the angle formed by the straight line a 1C and the bottom surface, that is, ≈ a1ca = 60.
In the right triangle A 1CA, A 1A=3, ∠ A 1CA = 60, so AC = 3.
AB is the base diameter, so ∠ cab = π 6.
Take A as the coordinate origin, and AB and AA 1 as the Y axis and Z axis, respectively, to establish a spatial rectangular coordinate system, as shown in the figure below:
Then a (0 0,0,0), c (32 32,32,0), a1(0 (0,0,3), b (0 0,2,0),
So AC=(32, 32, 0), A 1B=(0, 2, 3), CB=(- I have praised it and stepped on it. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem is not solved, please describe your problem in detail and provide free professional consultation through Baidu Legal Pro. Other similar problems 2011-04-17 are shown in the figure, and it is known that the point p is on the bottom circle o of the cylinder OO 1. AB is the diameter of the circle O. (1) It proves that BP is perpendicular to A1P302013-02-10 as shown in the figure, AB is the diameter of the circle O, and C is the circle 242010/. As shown in the figure, it is known that point P is on the bottom O of cylinder OO 1, AB is the diameter of circle O, and cylinder OO65438. ∠ AOP =12013201-10-02 It is known that the circle O with radius A is in the plane α, and the diameter is the endpoint A of AB, and then it is called PA⊥α, PA = A, C. (2) If it is known in 720 14-07-22 that a cylinder is inscribed on the ball O, and the diameter of the bottom surface of the cylinder and the radius of the ball are both 2, the surface area of the cylinder is 6, which is recommended for you: F.context('cmsRight', [{ ' URL ':/d 0 1373 f 082025 AAF 5 1 1 aa 256 e 9 EDAx-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? What impact will the "network toilet" have? The price of electric cars has dropped many times. Is the quality guaranteed? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720048856；