Why does log logx( 1-2x) in mathematics need x >? 0 and x are not equal to 1,

When a>0 and a are not equal to 1, a x = n is equivalent to x=log a(N).

In addition, if x= 1 in log x( 1-2x) (that is to say, a= 1 above), the value of n is constant no matter how the above x changes, which does not conform to the nature of logarithmic function.

It can be seen from the image of logarithmic function that x in log x( 1-2x) cannot take 0.

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