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(a? BC? )? ×(2a? BC? ) negative 2 power =? The most difficult math problem in history is the index!
I don't know where your negative secondary is, so there are two situations.

1.s =(a^3*b*c^3)^2=a^6*b^2*c^6 x =(2a? BC? ) negative quadratic = 1/(4 * A 4 * B 2 * C 4)

s*x= (a^2*c^2)/4

2.s=(a? BC? )? =a^6*b^2*c^6 y= 2a? BC?

(s*y)^-2= 1/(4*a^ 16*b^6*c^ 16)

Looks a little tired, but I can only write here, I hope it will be useful.