1 1. Angle α = 70+(180-130) =120.

12. Angle ABC= Angle DCE 1= Angle 2.

2 1.DE is parallel to BC, and the angle 1= angle 3 (internal dislocation angle), and the angle 1= angle 2 can be obtained: angle 2= angle 3, (I don't remember whether it is possible to get a parallel conclusion if the same angles are equal, it seems that there is), then it is judged that GF is parallel to CD, and angle CDB= angle GF \.

22. Angle 1+ Angle ADG= 90° Angle 2+ Angle B = 90 Because Angle 1= Angle 2, we can get Angle ADG = Angle b.

23. Let EF∨AB, in the same way, EF∨CD, parallel lines and the inner angle of the edge add = 180 degrees, and the two phases add to get 360.

6 =50 degrees (isosceles angle, angle 2= angle ACD)

7 The internal angles on the same side are complementary (the isosceles angles are equal, so that two straight lines are parallel).

8 180 degrees

9 180- burnt out

13 angle bed = 120+30= 150 degrees.

14 angle 1= angle 2, resulting in DE∑BC, so angle 3= angle 4.

20-degree angle BOC =180-52/2-60/2 =124 degrees (parallel, equiangular, angular bisector)

Another problem: BE∑AD, angle E= angle 2, angle B= angle a (inner angle) AB∑CD, angle A= angle 1, so ∠EDC =∠ 1+∠2 =∞.

22≈ 1 =∠2, ∴∠BAC=∠DEC=2*∠ 1 or ∠2, the congruence angle is equal, so DE is parallel to AB.

23 ≈1=1/2 ∠ aed =1/2 * 70 = 35 degrees, ∴1= ∠ 2, and the internal angles are equal, so

The above topics are all around the isosceles angle, internal angle and internal angle on the same side of parallel lines, which means you are not listening. This is not difficult.

The answer is hard, please give points.