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Several ninth grade math problems! ask sb. to do sth.
1, the square of (root number 3+root number 5 of 5) is equal to 95+20 times the root number 15.

2, because a+ 1/a= root number 10.

a2+ 1/a2+2= 10

a2+ 1/a2-2=6

(a- 1/a)2=6

The square root of a- 1/a = 6.

3. The root number four and two thirds is equal to the root number three.

4. Use Pythagorean Theorem

The square of c = the square of (2 radicals 3+ 1)+ the square of (2 radicals 3- 1) =26.

So c= root number 26

5. The square of x+5x-6 =(x+6)(x- 1)

Because x= radical number 5-1.

So x+6= radical number 5+5; X- 1= radical number 5-2

That is, the original formula = (radical number 5+5) (radical number 5-2)= three radical numbers 5-5.

6、 189=3×3×3×7

Because n is a positive integer, the root sign 189n is an integer.

So the minimum value of n is 3×7=2 1.

7. The radius should be1m..

So the total height is 3 times 3+2 of the root number 3 (difficult to draw and explain, please forgive me ~ ~)

8. If the length of the rectangle is x, the width is (0.06/x).

Judging from the meaning of the question:

2(0.06/x+x)= 1

Solution: x=2/ 10 or 3/ 10.

That is, the length of a rectangle is 2/ 10 or 3/ 10, and the width is 5 or 10/3 (the length and width can be reversed).

9,3x (2x+1) = 4x+2 can be changed to

(2x+ 1)(3x-2)=0

Solution: x 1=- 1/2 x2=2/3.

10, let the diagonal lines of the diamond be x and y respectively.

Judging from the meaning of the question:

x+y= 10

xy/2= 12

The solution is x=4 y=6.

Using Pythagorean Theorem:

The side length is the root sign 13.

The circumference is four times of the root number 13.

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Nothing upstairs is right ~ ~

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