The first drawing method is to write sin(2x+π/3) as sin2(x+π/6). Specifically, first draw an image of sinx-> zoom to the original 1/2- > and move the whole image left by π/6 units.

The second drawing is sinx->; Pan π/3 units to the left-> and then reduce the image to the original 1/2.

Cos(x/2-π/3)+ 1 is the same.

The first way to draw is to put

Cos(x/2-π/3) is considered as

Cos[ 1/2(x-2π/3)]. Draw the image of cosx first-> and expand it to twice the original, namely COS (x/2)->; Move the image to the right by 2π/3 units cos [1/2 (x-2π/3)]- > translate the whole image up by 1 unit.

cos(x/2-π/3)+ 1

The second drawing is similar to the above. Cosx pictures->; Move π/3 units to the right, and cos (x-π/3)- > enlarges the image to twice its original size.

cos(x/2-π/3)-& gt； Pan the whole image up by 1 unit.

cos(x/2-π/3)+ 1

In fact, just remember the first one. In the final analysis, the principle is the same. If you put the two together, you may get confused.

And remember to add left and subtract right, and add and subtract.