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Find the limit problem in advanced mathematics! ! The answer given is equal to 1, but I don't know how to get it. Find the process! ! )
This limit should be 0, and the function is continuously differentiable at x=0, so the answer is wrong.
Is there a mistake in the question? Sin (x)/x in x- >; The limit of 0 is 1.
(Differentiate numerator and denominator by Robita's law, (sinx)' = cosx, x' = 1, and when x = 0, cos0/ 1= 1).