(1) According to the meaning of the question, the random variable X obeys hypergeometric distribution.

The random variable X represents the number of boys, and the possible values of X are 0, 1, 2, 3, 4.

P(X=k)=Ck6？ C4？ k4C4 10，？ k=0， 1，2，3，4。

∴ So the distribution list of X is:

X 01234p121435 37 82114 (2) The allocation table knows that at least three boys should be selected.

That is, p (x ≥ 3) = p (x = 3)+p (x = 4) = 821+114 =1942.