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On the first day, a new operation math problem was defined.
3*4=3*(2+2)=(3*2)(3*2)={3*( 1+ 1)}{3*( 1+ 1)}=

(3* 1)(3* 1)(3* 1)(3* 1)=(3* 1)^4.

I don't know whether the number 1 is defined, so that any number A has a *1= A. If so, the answer is.

3 4 (that is, the fourth power of 3) is a bit like modern algebra!