1/ The departure time for picking up the car remains the same, so getting home 10 minutes earlier means that the one-way trip is 5 minutes shorter than before. If the scheduled time to go home from the station is X, the time to go home from the car halfway is X-0: 05;

2/ The original departure time was 6:00, and the arrival time was 6: 00+X. If the walking time was y, the departure time was 5:30, and the arrival time was 5:30+y+x-0:05, because the latter arrived home 10 minutes earlier than the former, that is, the latter added 0: 10.

3/ To sum up, according to the equation 6: 00+X = 5: 30+Y+X-0: 05+0:10 (both sides cancel X, and the term is moved to 6: 00-5: 30+0: 05-0:10 =

Actually, it doesn't need to be that complicated. It's easy to think about it from another angle.

Imagine that after his wife picked him up in the car, she took him to the station first and then went home. The bus left for ten minutes, so it took him five minutes to get to the station, and the time to get to the station was six o'clock, so his wife picked him up by car at five fifty-five.