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Mathematical problems of changing beer bottle caps for wine
10 yuan can drink 20 bottles. There are two calculation methods: the first method: 2 yuan 1 bottle of wine, 1 bottle of 4 bottles, 1 bottle of 2 bottles. The calculation is: 1 bottle 0.5 yuan, 1 bottle is 1 yuan, 65438+. So 10/0.5=20 bottles of beer. The second type: 10 yuan changes 5 bottles of beer, 5 bottles of 5 caps change 3 bottles of wine residue 1 bottle 1 lid, 4 bottles of 4 caps change just 3 bottles of wine, 3 bottles of 3 caps change 1 bottle of 3 caps change wine residue. After drinking 2 bottles of beer, 2 caps of 2 bottles are replaced with 1 bottle of wine residue, and 3 caps of 1 bottle of wine are finished. After drinking 1 bottle of wine, 4 caps are just replaced with 2 bottles of wine, and 2 caps of 2 bottles are replaced with 1 bottle of wine residue, and 1 bottle of wine residue is finished. * * * Number of drinking bottles = 5+3+3+1+2+1+2+1+kloc-0/+2-2 = 20 bottles of wine.