1) Because11555 = 5 * 22311= 5 * 3 * 7437 = 5 * 3 * 3 * 2479 = 5 * 3 * 37 *. So the sum of these two odd numbers is 333+335 = 668;

2) The year 2000 * * has 366 days, and the minimum product of year, month and day is 2000* 1* 1=2000, and the maximum product is 2000 *12 * 31= 744000. After checking, we can know that the product of three consecutive multiples of 5 is between 2000 and 744000, and only 2000 can be divisible.

30*35*40=42000,

40*45*50=90000,

70*75*80=420000,

80*85*90=6 12000,

Further observation shows that only the product of the year 2000 and the month and day can be decomposed.

42000=2000* 1*2 1;

90000=2000*3* 15;

420000=2000* 10*2 1;

6 12000=2000*306 cannot be decomposed into the product of 2000 and month and day.

So the end result is

June 2000 65438+1October 2 1, March 15, June 65438+1October 2 1 met the requirements, and the corresponding products were as follows.

30*35*40,40*45*50, 70*75*80。