If five numbers are different, if you choose four numbers, there are five ways to take them.

But the set of its sum has only four elements, which means that two of the five numbers are the same.

Then the sum of these five numbers has four situations.

①(44+45+46+47+44)÷4, which is not in line with the meaning of the question.

②(44+45+46+47+45)÷4, which does not meet the meaning of the question.

③(44+45+46+47+46)÷4=57, which fits the question.

(4) (44+45+46+47+47) ÷ 4, which does not meet the meaning of the question.

Subtract the element ③ in the set in turn, and you can get four numbers, 13, 12, 1 1, 10.

∫ 1 0+1+12+13 = 46 equals1less than 47, and 2 is greater than 44.

∴ 1 1≤ No.5 ≤1/

Only ∴ 1 1

The five numbers are 10, 1 1,1,12, 13.