Make an equilateral triangle on the left of AB. Remember another point as d, make the midpoint e of AD, and take a point f on the straight line be so that BF=BA. . . . After rotation, the corresponding point f of a is obtained. . .
Similarly, make an equilateral triangle with BC as the side, and get the H point corresponding to point C. .
Connecting BHF is a necessary triangle. . .