M crime? θ=ma，
Substitution data: a=2? m/s2
Suppose object b hits object a after t time,
From the speed formula: 0=v2-at,
Alternative data: t=2? s，
(2) The horizontal displacement of A is equal to the horizontal displacement of flat projectile B:
X=22v2t left os? 37 =2.a？ m，
B does flat throwing motion, which is a uniform linear motion in the horizontal direction, so the initial speed of flat throwing is:
v2=xt=2.a？ M/s,
(3) The height difference between the initial positions of objects A and B is equal to the sum of the rising height of A and the falling height of B,
So the height difference between objects A and B is: h=22v2tsin? T2 = 37+22 of 37+22? m，
Answer: (2) The time t for sliding to the highest point on object A is 2? s；
(2) When object B is thrown, the initial velocity v2 is 2.a? M/s;
(3) The height difference between the initial positions of objects A and B is 2.d? Meter (short for meter))