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The second grade mathematics expansion problem book 2.
A * * * has 22 small animals, 6 in each big room and 4 in each small room. How can I arrange housing?

The first arrangement: 3 large rooms+1 small room.

Arrange three large rooms, which can accommodate 3×6= 18, leaving 22- 18=4.

Arrange 1 small room, just enough for 4 people.

The second arrangement: 1 large room +3 small rooms.

Arrange 1 large room, which can accommodate 1×6=6, leaving 22-5= 16.

Arrange 4 small rooms, which can just accommodate 4×4= 16.

The third arrangement: 4 large rooms

4×6=24, that's enough.

The fourth arrangement: 6 small rooms

4×6=24, that's enough.