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Answers to the true questions of mathematics in senior high school entrance examination
) ∫ point d coincides with point a to get crease EN,

∴DM=4cm,NM=3cm,

∵EN⊥AD,

∴MN= =3,

It can be seen from the properties of folding and parallel lines that ∠END=∠NDC=∠NDE,

∴EN=ED, let EM=x, then ED=EN=x+3,

ED2=EM2+DM2 comes from Pythagorean theorem, that is, (x+3)2=x2+42.

The solution is x=0, that is, em = 7/6 cm.