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Help me solve a 7 yuan linear equation, X0 to X4 are known numbers, and my brain is bleeding. Help a math genius! Is there a master to help? Use it tomorrow.
A+b+c=2 radicals a+ 1 plus 4 radicals b+ 1 plus 6 radicals c-2 minus 14,

[(a+ 1)-2 (A+ 1)+[(B+ 1)-4 (b+ 1)+4]+[(c-2)-6 (.

[root (a+ 1)- 1]2+[ root (b+ 1)-2]2+[ root (c-2)-3] 2 = 0.

So: root (a+ 1)- 1=0, root (b+ 1)-2=0, and root (c-2)-3=0.

Solution: a=0, b=3, c= 1 1.

a(b+c)+b(c+a)+c(a+b)

=0+3* 1 1+ 1 1*3

=66

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