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( 1)≈∠AOC = 90,∠BOC=60,

∴∠AOB=90 +60 = 150,

∫OM average score ∠AOB,

∴∠aom= 1 ^ 2∠AOB = 75

∴∠MOC=90 -75 = 15,

And ∫ON∠BOC,

∴∠NOC= 1 2 ∠BOC=30,

∴∠MON=∠MOC+∠NOC= 15 +30 =45,

So the answer is: 45;

(2)∫∠AOC = 80,∠BOC=60,

∴∠AOB=80 +60 = 140,

∫OM average score ∠AOB,

∴∠AOM= 1 2 ∠AOB=70,

∴∠MOC=80 -70 = 10,

And ∫ON∠BOC,

∴∠NOC=∠BOC=30,

∴∠MON=∠MOC+∠NOC= 10 +30 =40,

So the answer is: 43;

(3)∫∠AOC = 70,∠BOC=50,

∴∠AOB=70 +50 = 120,

∫OM average score ∠AOB,

∴∠aom= 1 ^ 2∠AOB = 60

∴∠MOC=70 -60 = 10,

And ∫ON∠BOC,

∴∠NOC= 1 2 ∠BOC=25,

∴∠MON=∠MOC+∠NOC= 10 +25 =35,

So the answer is: 35;

(4) Conclusion ∠MON= 1 2 ∠AOC,

So the answer is: ∠AOC ..