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A math problem is urgent! Must be adopted
(1) Traffic, trains come and go.

① Transportation fee: According to the meaning of the question, three adults 1 child buy half a ticket.

(482×3+482÷2)×2

=( 1446+24 1)×2

= 1687×2

=3374 (yuan)

② Accommodation: Depart on the 7th and return for 7 days on the 3rd. Stay 13 days and stay at home for 6 days. Transportation fee 8- 12 days ***5 days.

50×2×6+90×4×7+50×4×5

=600+2520+ 1000

=4 120 (yuan)

③ Admission fee: 8- 12 ***5 days.

60×4×5= 1200 (yuan)

Total: 3374+4120+1200 = 8694 (yuan)

(2) All round trips are by plane.

① Air ticket (transportation fee): 3 adults, 1 child.

( 1320×0.55×3+ 1320÷2)×2

=(726×3+660)×2

=2838×2

=5676 (yuan)

② Accommodation: 4 120 yuan.

③ Tickets: 1200

Total: 5676+4120+1200 =10996 (yuan)

(3) Take the train when you go and fly back.

① Train ticket: 482×3+482÷2= 1687.

② Air ticket:1320× 0.55+1320 ÷ 2 = 2838.

③ Accommodation: 4 120 yuan.

④ Tickets: 1200

Total:1687+2838+4120+1200 = 9845 (yuan)

9845 & lt 10000, so bring 10000, according to the above budget is enough.