3a = 2 and a = 2/3, so the proportional resolution function is: y = (2/3) x.
K/3 = 2 and K = 6, then the inverse analytic function is: y = 6/x.
(2) The intersection of two functions is (3,2). As can be seen from the figure, when 0 ≤ x
(3) c (3,0), M(m, n), that is, BM = m, DM = 3-m.
S quadrilateral OADM=S rectangle OBDC-(S triangle OBM+S triangle OAC)
= 3n-( 1/2 * 3 * 2+ 1/2 * m * n)
=(6n-mn)/2-3=6
That is, 6n-mn= 18( 1).
N=6/m, that is, mn=6(2)
The solutions are n = 4, m = 3/2 and 3-m = 3/2.
That is, BM=DM=3/2.