3a = 2 and a = 2/3, so the proportional resolution function is: y = (2/3) x.

K/3 = 2 and K = 6, then the inverse analytic function is: y = 6/x.

(2) The intersection of two functions is (3,2). As can be seen from the figure, when 0 ≤ x

(3) c (3,0), M(m, n), that is, BM = m, DM = 3-m.

S quadrilateral OADM=S rectangle OBDC-(S triangle OBM+S triangle OAC)

= 3n-( 1/2 * 3 * 2+ 1/2 * m * n)

=(6n-mn)/2-3=6

That is, 6n-mn= 18( 1).

N=6/m, that is, mn=6(2)

The solutions are n = 4, m = 3/2 and 3-m = 3/2.

That is, BM=DM=3/2.