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Mathematical circle problem
First, calculate the sum of the middle two numbers. The question is 1 1.

Because the sum of the five on the left is 25 and the sum of the five on the right is 30, the sum of the left and right of the middle one calculated twice is 55 (the sum of1-10 is 55), that is to say, when the number of the middle two is calculated for the second time, it is actually 5 and 6, which is the middle one. So it can be 1, 10 or 2,9, or 3,8, or 4,7.

Then you can choose the sum of three numbers, namely 14 and 19.

For the above four situations, in fact, the answer to each situation is not unique.

So there are actually many answers.

For example: 2,3,91-104,7,8 or 2,4,81-103,7,9.

1, 3, 10 2-9 4, 7, 8 or 3, 4, 7 2-9 1, 8, 10.

etc

This happens because the middle two numbers get 5 and 6. So that their sum is only the sum of 25+30=55= 1 to 10, just like taking two numbers from 1 to 10 and putting them in a special position, and then the sum of their 10 numbers remains unchanged, the only difference is which two numbers are taken.

So many answers to this question come from this.