y 1= ae^(-nt)
y2 = a-y 1
= ae^(-nt)
(2)
At 5 minutes, the water in bucket 1 is equal to the water in bucket 2.
= & gty 1(5) = y2(5)
ae^(-5n) = a-ae^(-5n)
2e^(-5n) = 1
n= [ln(2)]/5
y 1= a/8
ae^(-nt) = a/8
e^(-nt) = 1/8
t = [ln8]/n
=ln8 / [[ln(2)]/5]
= 15
In 10 minutes, the water in the bucket 1 will be a/8.