y 1= ae^(-nt)

y2 = a-y 1

= ae^(-nt)

(2)

At 5 minutes, the water in bucket 1 is equal to the water in bucket 2.

= & gty 1(5) = y2(5)

ae^(-5n) = a-ae^(-5n)

2e^(-5n) = 1

n= [ln(2)]/5

y 1= a/8

ae^(-nt) = a/8

e^(-nt) = 1/8

t = [ln8]/n

=ln8 / [[ln(2)]/5]

= 15

In 10 minutes, the water in the bucket 1 will be a/8.