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A math problem in grade seven (looking for rules)
-3- 1=-4

-3- 1+2=-2

-3- 1+2-3=-5

-3- 1+2-3+4=- 1

-3- 1+2-3+4-5=-6

And so on,

The law of odd time is as follows

The number 1 3 5 7 ... the result is -4 -5 -6 -7 ... Every time you type 1, you learn less and less.

At 2468th Street ..... the result is -2-1 0 1 2 ..... increasing 1 every time.

Odd and even shift results are regularly separated,

Twentieth -2-1 0 1 even tenth -2+9=7

If s=64, the result must be even -2+(66)=64. That is to say, the 67th number is 64 and the 67th even number is 134, so after moving 134 times, s=64. I don't know if the result is right, the analysis process should be very clear. Please take it and add more.