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Shandong mathematics volume answer
(1) Let the number of items needing rough machining be x kg.

x+(3x+2000)= 10000

4x=8000

x=2000

Therefore, the number of items requiring rough machining is 2000 kg.

(2) Let warehouse A store X tons of grain and warehouse B store Y tons of grain.

The score is not easy to write, three fifths is written as 0.6, and two fifths as 0.4.

x+y=450

x-0.6x=y-0.4y

X-0.6x = y-0.4y-0.4x = 0.6y-4x = 6y-x =1.5y-substitute x+y=450.

x+ 1.5x=450 - 2.5x=450

x= 180

y=270

Therefore, warehouse A originally stored grain 180 tons, and warehouse B originally stored grain of 270 tons.

0.6x+0.4y = 108+ 108 = 2 16 & gt; 200

So this transfer can meet the needs of warehouse C.