I understand what it means to write in another form, that is to say, the three numbers have not changed, but the order of the lines has changed, so we must find a one-to-one correspondence.

Look at the first set of numbers, 1, a+b, a, which of these three numbers can correspond to the last set of numbers? First of all, 1 is not equal to 0, and b/a appears in other numbers, which means that a can't be 0, so only a+b=0 holds.

Because a+b=0 holds, the number of two groups is only 1. A needs to find the corresponding relationship between b/a and B. Because a+b=0 and a=-b, b/a=- 1 becomes 1. The correspondence between A and-1 and B can only be a=- 1 and b= 1.

So a+b=0 and ab=- 1.

(a+b)^2008+(ab)^2009-(a+b-ab)+x^2

=0- 1-(0+ 1)+4=2