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Mathematical bricklaying
Everyone carries 4 yuan, and 5 of them have to move twice.

Therefore, the total number of bricks moved at this time = (total number of bricks moved +5)×4.

If each class costs 5 yuan, two people have no bricks to move.

So the total number of bricks moved at this time = (total number of bricks moved -2)×5.

That is, (total number of brick movers +5)×4= (total number of brick movers -2)×5.

The number of brick movers =5×4+2×5=30.

Then the total number of bricks =(30+5)×4= 140 people.