24 kg

Let the concentration of solution A be A, the concentration of solute B be B, and the mass of the poured solution be M, then the mass of the solution poured from A is M, the mass of the poured solute is am, the mass of the remaining solution is 40-m, and the mass of the remaining solute is A (40-m); The mass of solution poured out from B is m, the mass of solute poured out is bm, the mass of residual solution is 60-m, and the mass of residual solute is b(60-m). After mixing, bottle A contains 40kg solution and (a (40-m)+BM) kg solute; Bottle B contains 60kg solution and solute (am+b(60-m)). Because the mixed beverage contains the same concentration of fruits and vegetables, it has (40a+(b-a)m)/40=(60b+(a-b)m)/60, and m=24kg. (Simple method: Assuming AB concentration, it can also be calculated).

two

132cm

The ground is D, the plane is O, if DA=5a and OB=5B, then DB=4a and OC=4b, so for point A, the ground is 5a=68+4b+20. . . ① For point B, the distance from the ground is 4a=20+5b. . . ② At the same time, ① ② a=40, and B = 28. DC=4b+20=4X28+20= 132cm